Why would someone choose to use a graphing calculator to solve a system of linear equations instead of graphing by hand? Explain your reasoning. Why would someone choose to use a graphing calculator to solve a system of linear equations instead of graphing by hand? Explain your reasoning.

We would prefer to use a graphing calculator because it will give a more exact solution, because it is easier to read, and because it is faster to do.

There are multiple ways, one of them is by graphing the lines and seeing where the lines intersect.

Now, there are two ways of doing this, graphing by hand and using a graphing calculator.

There are cases where graphing by hand is enough, but is more time-consuming than using a graphing calculator. But there are cases where the intersection happens at a point with irrational values, these cases is really hard to find the solution in a graph by hand (as it can have mistakes and you can't zoom in). While if you used a graphing calculator, you could zoom is as much as you want, so you would get a really good estimation for the solution.

If you want to learn more about systems of equations, you can read:

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something that characterises a right triangle is the fact that we may use pythagoras' theorem to find any one of its sides given that we have the length of the other two sides. here, we have the length of the hypotenuse, √(87) yd, and one other side, √(23) yd, thus we can easily find the length of the remaining side using pythagoras' theorem as defined below:

c^2 = a^2 + b^2, where c is the length of the hypotenuse, and a and b are the lengths of the other two sides.

thus, given that c = √(87) and a = √(23), we may substitute these into the formula we defined above to get:

c^2 = a^2 + b^2

(√87)^2 = (√23)^2 + b^2 (substitute c = √87 and a = √23 into the equation)

87 = 23 + b^2 (evaluate (√87)^2 = 87 and (√23)^2 = 23 - remember that the square root of a number, squared will equal that very same number)

64 = b^2 (subtract 23 from both sides)

√64 = b (take the square root of both sides)

8 = b (evaluate √64 = 8)

therefor, the length of the unknown leg in the right triangle is 8 yd (first answer).