There were 200 melons in a box and they were distributed to 3 children in the ratio of 4:3:3. The first child sold the melons at 2$ each while the other two sold the melons at 2 for 5$. find the total amount of money collected fro. the sales of all melons.

$460

Step-by-step explanation:

let the number of melons be x

4x + 3x + 3x = 200 melons

10x = 200 so, x will be 20

4x = 80 melons

3x = 60

3x = 60

amount made by 1st child = 80 × $2 = 160$

the remaining melons are 60 + 60 = 120

amount collected: they sold them in groups of 2 and each group was $5. so,

120÷2 × $5 = $300

total amount = 300 + 160 = $460.

x = -3

y = -18

step-by-step explanation:

to solve by substitution, substitute one variable and solve for the other. then substitute again to find the remaining variable.

x-1/3(3x-9) = -3 since y=3x-9 substittute y.

x-1/3(3x-9)=-3

x + x +3 = -3

2x+3=-3

2x+3-3= -3-3

2x=-6

x=-3

substitute again into y=3x-9

y=3(-3)-9

y=-9-9

y=-18

my guess would be b and d, but i didn’t actually get out the pen and paper. lol