Maureen's job is to provide technical support to computer users. Suppose the arrival of calls can be modeled by a Poisson distribution with a mean of 5.4 calls per hour. What's the probability that in the next 20 minutes there will be 2 or more calls

Step-by-step explanation:

We would convert 20 minutes to hour.

60 minutes = 1 hour

20 minutes = 20/60 = 1/3 hour

Let x represent the number of calls received in 20 minutes or 1/3 hour

If the mean number of calls per hour is 5.4, then the number of calls received in 20 minutes is

5.4 × 1/3 = 1.8

The probability that there will be 2 or more calls is expressed as P(x ≥ 2)

From the Poisson distribution calculator,

P(x ≥ 2) = 0.54

the answer is 0.3175 hope that you ^w^

also you might actually want to put this picture up if you want people to solve it luckily i remember this question

is it 35

step-by-step explanation: