In right triangle ABC, ∠A is a right angle and sinC=15/17. What is the ratio cos C?

Step-by-step explanation:

From the triangle, given sin C=15/17 we will use the trigonometry identity to get the ratio of cosC. Using the SOH CAH TOA identity;

sinC = opp/hyp = 15/17

opposite = 15

hypotenuse = 17

According to pythagoras theorem;

hyp² = opp²+adj²

17² = 15² + adj²

adj²= 17²-15²

adj = √64

adj = 8

Since cosC = adj/hyp

cosC = 8/17

The ratio of cos is 8/17

step-by-step explanation:

i have done this all on a piece of paper but idk how to put it on here cuz it needs to be drawn