What is the product of (5 m Superscript negative 2 Baseline) (2 m Superscript negative 3 Baseline)? StartFraction 7 Over m Superscript 5 EndFraction

7m6

StartFraction 10 Over m Superscript 5 EndFraction

10m6

C ) 10/m⁵

Step-by-step explanation:

In this question, we have to find the product of two terms

First term = 5 m⁻²

Second term = 2 m⁻³

Product of both terms = (5 m⁻²) · (2 m⁻³)

The simple way of calculating product of these two term which involves constants as well as variable is that we multiply the constants together:

5·2 = 10

And we multiply the variables. According to the rules of multiplication, when 2 same constants or variables are multiplied, we can just add their powers to get the result.

(m⁻²) · (m⁻³) = m⁻²⁻³ = m⁻⁵

The product of both terms can be written as:

(product of constants)(product of variables) = (10)(m⁻⁵) = 10/m⁵

So the correct option is C

first option

a function is a relation in which an input is paired with exactly one output.

so, let's find the right answer.

in our first option, our inputs are january, february, and march. the outputs are 30, 28, and 25. each input has it's own output. this is correct!

our second option we know is incorrect, because ms. valverade has two outputs, dogs and cats. this is not a function.

our third option is incorrect as well. the yellow square has two ouputs, the square and the triangle.

lastly, in our fourth option, we see the number 7 two times with a different output. therefore, this is not a function.

remember: each input must be paired with only one output!

c > -10.55

step-by-step explanation: