Match the circle equations in general form with their corresponding equations in standard form. x2 + y2 - 4x + 12y - 20 = 0
(x - 6)2 + (y - 4)2 = 56
x² + y² + 6x - y - 10=0
(x - 2)2 + ( + 6)2 = 60
3x2 + 3y2 + 12x + 18y - 15 = 0
(x + 2)2 + (y + 3)2 = 18
5x2 + 5y2 - 10x + 20y - 30 = 0
(x + 1)2 + (- 6)2 = 46
2x2 + 2y2 - 24x – 167 - 8 = 0
x² + y2 + 2x - 12y-g=0

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet

the answer is y < -3 or   y > 3

-3y > 7 + 2

-3 y > 9

y < -3

idk man good luck man

b and c

step-by-step explanation: