In STU, SU =18 and TU =13. Find m

m=22.2

Step-by-step explanation:

By using the Pythagorean’s theorem i.e

hypotenuse^2=opposite^2+adjacent^2

Where

Hypotenuse =unknown

Opposite =18

Adjacent =13

Hyp^2=18^2+13^2

Hyp^2=324+169

Hyp^2=493

Hyp=sqrt 493

Hyp=m=22.2

351.23

step-by-step explanation:

solution:

→c= a b , that is product of a and b is possible only when when a is m × n matrix and b is n × p matrix.

that is, number of columns of a= number of rows of b.

so, size of matrix , c= a b is , if a = (m × n)matrix

b= (n × p)matrix

then a b = [ (m × n)matrix] ×[   (n × p)matrix ]

→→c= a b= [m × p ] matrix

→→size of product a b will be equal to = number of rows of a × number of columns of b