If x = 45, y = 63, and the measure of AC = 4 units, what is the difference in length between segments AB and AD? Round your answer to the nearest hundredth.

Difference in the length of AB and AD will be 1.17 units

Step-by-step explanation:

From the figure attached,

In ΔABC and ΔADC,

x = 45°

y = 63°

AC = 4 units

By applying Sine rule in ΔABC,

SinB =

Sin(x) =

Sin(45)° =

AB = 4√2 ≈ 5.657 units

Similarly, by applying sine rule in ΔADC,

Sin(y)° =

Sin(63)° =

AD =

     = 4.489 units

AB - AD = 5.657 - 4.489

             = 1.168

             ≈ 1.17 units

Therefore, difference in the length of AB and AD will be 1.17 units

it would open into a square depending on the type of envelope i’m not sure about the second part