Suppose a student completes an experiment with an average value of 2.3 mL and a calculated standard deviation of 0.70 mL. What is the maximum value within a 1 SD range of the average

6^2 or 36

step-by-step explanation:

6000n

6×1000n

6×10^3 n

so we need 6n need to be a perfect cube

so n has to be 6^2 so that 6n is 6^3

what i'm saying is if you let n be 6^2 you have 6^3×10^3 or 60^3 which is a perfect cube

answer:

probably the same as it is today since you did not eat the corn dogs yet

step-by-step explanation:

i would be 2,000 just get the square root of 50 which is 2500 and the divid 4/5 and last thing multiply the answer you get for that by the square root of 50

step-by-step explanation:

answer: correct

step-by-step explanation: