Martha has $10,000 saved and wants to attend a college with a current tuition of $10,000 a year. She will graduate from high school in five years. Roughly how much more will Martha need to save for one-year’s tuition to account for an annual rate of inflation of 3%? A. $1,590.00

B. $1,255.00

C. $300.00

D. $3,000.00

A: 1,590.00

Step-by-step explanation:

We can use the simple interest rate equation for this problem: p(1 + r)^t

Step 1: Replace the variables with the amounts given

10000(1 + 0.03)^5

Step 2: Solve/Plug in calc

You will get 1590.00

37/3

step-by-step explanation:

step 1: simplify both sides of the equation.

7x+8(x+

1

4

)=3(6x−9)−8

7x+(8)(x)+(8)(

1

4

)=(3)(6x)+(3)(−9)+−8(distribute)

7x+8x+2=18x+−27+−8

(7x+8x)+(2)=(18x)+(−27+−8)(combine like terms)

15x+2=18x+−35

15x+2=18x−35

tep 2: subtract 18x from both sides.

15x+2−18x=18x−35−18x

−3x+2=−35

step 3: subtract 2 from both sides.

−3x+2−2=−35−2

−3x=−37

step 4: divide both sides by -3.

−3x

−3

=

−37

−3

x=

37

3

hello from mrbilldoesmath!

answer:

25x^2 + 90x + 84

discussion:

mn(x) = m(n(x)) = m( 5x + 9) =

(5x + 9)^2 + 3 =>

25x^2 + 90x + 9^2 + 3 =

25x^2 + 90x + 84                 (as 9^2 = 9*9 = 81)

which is the second choice

regards,  

mrb

p.s.   i'll be on vacation from friday, dec 22 to jan 2, 2019. have a great new year!