At what point of the curve y = cosh(x) does the tangent have slope 3?

(1.82, 3.17)

Step-by-step explanation:

Given the curve:

y = cosh(x)

we need that the tangent has slope 3. The tangent of a curve in a given point is found with its derivative.

dy/dx = sinh(x) = 3

From the plot of sinh(x), we get:

x ≈ 1.82

Replacing into cosh(x), we get:

y = cosh(1.82) ≈ 3.17

Then, at point (1.82, 3.17) the tangent is 3