The equation of a line is y=3. Write an equation in slope intercept form of a line parallel to y=3 that passes through (0,6).

y = 6

Step-by-step explanation:

We have to consider the equation of a line ( in slope - intercept form ) that is parallel to y = 3, and passes through the point ( 0, 6 ). Now y = 3 can be plotted as a horizontal line that passes through the point ( 0, 3 ). If we want a line that is parallel to this, it must be horizontal as well;

Let us consider the second point now. This line must pass through the point ( 0, 6 ). We can conclude that the line must be 1. Horizontal, and 2. Pass through point ( 0, 6 );

Equation - y = 6

what is the approximate angle of acb if abc is 25cm and the length of segment bc is 15

step-by-step explanation:

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