if the point (-3,4) is the vertex point of the curve of aquadratic function f and -5 is aroot of the equation f(x) =0, then what is the other root

x = - 1

Step-by-step explanation:

The x- coordinate of the vertex is mid way between the roots of the quadratic.

The difference between x- coordinate of vertex and the given root is

difference = | - 3 - (- 5) | = | - 3 + 5 | = | 2 | = 2

Thus the other root is 2 units to the right of x = - 3, that is

x = - 3 + 2 = - 1

The other root is x = - 1

3x^3-x^2+6x-9