A mixture contains 21.7 g NaCl, 3.74 g KCl, and 9.76 g LICI.

How many total moles are in this

mixture?

Total moles = 0.6504 moles

Step-by-step explanation:

Molar mass of NaCl = Molar mass of Na + Molar mass of Cl

Molar mass of NaCl = 22.99 + 35.45 = 58.44 grams/moles

No. of mole of Nacl = grams/molar mass

No. of mole of Nacl = 21.7/58.44 = 0.371 mol

Similarly calculate for other two

Molar mass of KCl = 39.1 + 35.45 = 74.55 grams/moles

No. of mole of Kcl = 3.74/74.55 = 0.0502 mol

Molar mass of LiCl = 6.941 + 35.45 = 42.39 grams/moles

No. of moles of LiCl = 9.76/42.39 = 0.2302 mol

Total moles = 0.371 + 0.0502 + 0.2302

Total moles = 0.6504 moles

heyyy

step-by-step explanation:

ratio is 2 : 9

the answer is three

13.5 : 3