Leo is constructing a tangent line from point Q to circle P. What is his next step? Mark the point of intersection S of the segment created from the arcs and circle R, and construct line RS.

Mark the point of intersection S of circles R and P, and construct line QS.

Construct arcs from point Q that are greater than half the length of segment PQ.

Construct a circle from point P that has a radius of P and the intersection of circles P and R.

Mark the point of intersection S of circles R and P, and construct line QS.

Step-by-step explanation:

In the figure attached, the problem is shown. The construction of the tangent lines from point Q to circle P is almost done. The last step is to draw the lines that pass through point Q and the intersection of the circles.

0.16 or 16%

step-by-step explanation:

lets take a coin for example.

if you toss it twice, it has a 1/4 chance of landing on heads both times because 1/2 * 1/2 is 1/4.

with the cards, the chance of picking dog is 0.4. having two people pick one is like picking a card twice in a row. so 0.4 * 0.4 is 0.16, or 16%

for the friend request.

when a figure, such as triangle (xyz) is reflected over the line y = x to create x'y'z' the x-coordinates and y-coordinates of the original image (pre-image) will be reversed for the image. (e.g., (x, y) > (y, x)) this means that the pre-image position of the x- and y-coordinates switch places which in turn provides a mirror like image of the original xyz.  

i notice that when i draw a line segment from x to x', that the points are parallel from each other -- they are exactly across from each other and do not intersect with any other points.  

yes, think i would see the same characteristic if you drew the line segment connecting y with the reflecting line and then y' with the reflecting line because of the essence of reflections. because it is a mirror image, each point was effected the same way which leads me to conclude that they same would apply to y and y'.