Smith is a weld inspector at a shipyard. He knows from keeping track of good and substandard welds that forthe afternoon shift 5% of all welds done will be substandard. If Smith checks 300 of the 7500 welds completedthat shift, what is the probability that he will find less than 20 substandard welds

0.9066

Step-by-step explanation:

According to the question, the data provided in the question is as follows

Probability =  p = 0.05

Sample size = n = 300

Total welds = 7,500

Based on the above information, the probability for less than 20 substandard welds is

As per binomial distribution, the normal approximation is

= 15

= 3.77

= 1.32

Therefore, the probability is 0.9066

10cm

step-by-step explanation:

ik

you didn't post any answer choices, so its not 100% clear what your teacher is looking for

however, log(15/7) is equivalent to log(15) - log(7)

i'm using the rule log(x/y) = log(x) - log(y)