Select the correct answer from each drop-down menu, AABC has vertices at A(11,6), B(5,6), and C5, 17).
AXYZ has vertices at XL 10,5), 7-12, 2), and 2-4, 15),
AMNO has vertices at M-9,-4), M 3,-4), and 3, 15),
AJKL has vertices at 17, 2), K[12,-2), and (12,7).
APOR has vertices at 12, 3), 12, 2), and R3, 2),
Can be shown to
can be shown to be congruent by a sequence of reflections and translations,
be congruent by a single rotation

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c

step-by-step explanation:

there is vertical asymptote at x = 2 and x = 0

vertical asymptote occurs at the points where the denominator is 0. so we can say that

x = 2 occurs when there is a factor (x-2) in the denominator, and

x = 0 occurs when there is a factor "x" in the denominator

thus, the denominator of the equation would have "x * (x-2)", this is option c only. that's the correct answer.

the area of a triangle is determined by the formula: base x height * 1/2

you'll need to assign a base to the triangle. based on the vertices given, the simplest base would be the line segment from (-2,1) to (2,1). the distance between any two numbers is found by just subtracting them. here, you should subtract the x values to find the distance of this side.

2 - (-2) = 4.

so the distance (aka the length of the base) is 4. the height of the triangle is the distance between the base and the highest point on the triangle which is (3,4). we should subtract the y values this time to find the height/distance.

4 - 1 = 3

so the height is 3.

base = 4

height = 3

hope this if needed hmu