HELP PLEASEFor a quadratic equation of the form 0 = ax2 + bx + c to have two zeros, what must be true?

Option (4)

Step-by-step explanation:

If a quadratic equation is represented by,

ax² + bx + c = 0

Then discriminant of this equation will be = b²- 4ac

Discriminant of a quadratic equation tells the type of roots the equation has.

1). If b² - 4ac > 0,

  Equation will have two distinct real roots

2). If b² - 4ac = 0

  Equation will have one real root

3). If b² - 4ac < 0

  Equation will have no real roots or there will be two imaginary roots.

For two real roots,

b² - 4ac > 0

b² > 4ac

Therefore, Option (4). 4ac < b² will be the answer.

r(0,90)(x,y) . t(-5,0)

last option

step-by-step explanation:

∆def to ∆d"e"f"

- rotate 90 counterclockwise degrees

- then translated 5 to the left (x --> x - 5)

answer is the last option

5

step-by-step explanation: