1. Find the component form of the vector that represents the velocity of an airplane descending at a speed of 100 mph at an angle of 45° below the horizontal. (Leave answers in exact form)

The component form should be <70.71, -70.71>

horizontal component = module ( cos(angle))

= 100 (cos(-45))

= 70.71

And,

vertical component = module (sin(angle))

= 100 (sin(-45))

= -70.71

Learn more: link

<70.71, -70.71>

Step-by-step explanation:

The vector has a module of 100 and a angle of -45° (negative because it is below the horizontal). So, to find its components, we need to use the sine and cosine relation of its angle:

horizontal component = module * cos(angle)

horizontal component = 100 * cos(-45)

horizontal component = 70.71

vertical component = module * sin(angle)

vertical component = 100 * sin(-45)

vertical component = -70.71

So the vector in the component form is <70.71, -70.71>

The negative sign of the vertical component means its direction is downwards.

step-by-step explanation:

through just a quick inspection, one can see that the graph of this cubing function starts in quadrant iii and ends in quadrant i.   when x = 0, y = 3, so the y-intercept is (0, 3).

if graphs are part of the problem statement, share them.   .

answer: idk

step-by-step explanation: