What is the factorization of the expression below? 16x^2 - 49
A. (8x + 7)(2x-7)
O B. (4x + 7)(4x - 7)
O C. (8x-7)(2x-7)
O D. (4x-7)(4x-7)

B

Step-by-step explanation:

16 x² - 49 ← is a difference of squares and factors in general as

a² - b² = (a + b)(a - b), thus

16x² - 49

= (4x)² - 7²

= (4x + 7)(4x - 7) → B

answer: standard form is ax^2 + bx + c = 0

step-by-step explanation:

standard form is ax^2 + bx + c = 0

(2x + 1)(x - 2) = 0

distribute to get into standard form

2x^2 - 4x + x - 2 = 0

2x^2 - 3x - 2 = 0

a = 2, b= -3, c = -2

a is your answer

step-by-step explanation:

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