ILL GIVE AS MANY POINTS AS U WANT PLZ HELP MEEE I don't use this please help

Ok, "steeper than y = x^2" means that the function grows "faster" than y = x^2. and we can look at this by looking at the derivates, if the derivate is larger, then it is steeper.

The derivate of y = x^2 is: y´= 2x.

Now let's look at the other functions.

a) y = (1/2)*x^2

the derivate is:

y' = 2*(1/2)*x = x

this function is less steep than y = x^2

b) y = -x^2

the derivate is:

y' = -2x

So we have, in absolut value, exactly the same than for y = x^2.

The difference is that here the function decays instead of growing, so this is "less steep than y = x^2)

c) y = (2x)^2 = 4*x^2

the derivate is:

y´= 2*4*x = 8*x

this is steeper than y = x^2-

d) y = 2x^2

the derivate is:

y´= 2*2*x = 4x.

this is steeper than y = x^2

e) y = (x/2)^2 = (1/4)*x^2

the derivat is:

y' = (2/4)*x = (1/2)*x

so this is lees steep than y = x^2

d

step-by-step explanation:

d

  y= -3x is the required function.

step-by-step explanation:

we have been given a table:

x             y

0             0

1             -3

3             -9

-2             6

we can see that the values of y is -3 times the value of x

hence, the function would be: y= -3x.

put the values of x will give the same y as in the table that means function is satisfying the given table.