Field book of an agricultural land is given in the figure. It is divided into 4 plots . Plot I is a right triangle , plot II is an equilateral triangle, plot III is a rectangle and plot IV is a trapezium, Find the area of each plot and the total area of the field.( use √3 =1.73) plse and mee its urgent

Total area = 237.09

Step-by-step explanation:

Area of equilateral triangle is given as:

is equilateral triangle with side = 13 cm

Side EA = ED + DA

CDEF is a rectangle, so CF = ED

EA = CF+DA

19=7+DA

DA = 12 cm

Looking in the region I, i.e. right angle .

According to pythagoras theorem:

Area of a right angled Triangle:

Area of rectangle is given as: Length Width

For finding area of trapezium i.e. region IV, let us draw a line parallel to side FG at E that will cut GH at a point P and 'h' is the height of triangle or distance between parallel sides of trapezium.

Now, we have a triangle EPH whose 3 sides are given as a=12, b=9 and c=15.

Using hero's formula for area of a triangle:

Comparing with:

h is distance between parallel sides of trapezium.

Area of trapezium:

Total area =

it's d.

step-by-step explanation:

because: -1(4x + 1y) +2 (1x-3y) distribute each number into the parenthesis.

then you would get: -4x - 1y + 2x -6y combine like terms

and get: 2x -7y

hope my answer has you if not then i'm sorry.