the equation of straight line passing through the point (2,3)&perpendicular to the line 4x-3y=10 is

4y = -3x +18

Step-by-step explanation:

Let's get the gradient from this line equation first.

4x-3y=10

4x-10=3y

Y= 4/3x -10/3

The gradient is 4/3.

For a line perpendicular to another line.

M*M'= -1

M= -/(4/3)

M = -3/4

So the gradient to be used is -3/4

Formula for solving is

(Y-y1)/(x-x1)= M

X1= 2

Y1= 3

M = -3/4

(Y-y1)/(x-x1)= M

(Y-3)/(x-2)= -3/4

4(y-3)= -3(x-2)

4y -12 = -3x +6

4y = -3x +18

any options?

step-by-step explanation: