find the area of triangle two sides of which are 8cm and 11cm and the perimeter is 32cm with Herons formula

8√30

Step-by-step explanation:

The length of the third side is 32 - 8 - 11 = 13. s (which is half of the perimeter) is 32 / 2 = 16 so the answer is:

√s(s-a)(s-b)(s-c) = √16 * (16 - 8) * (16 - 11) * (16 - 13) = √16 * 8 * 5 * 3 = √1920 = 8√30

step-by-step explanation:

use pothagarean therom

a^2+b^2=c^2 so first ac

acm is a right triangle because c= 90°

and am (the hypotenuse or c) =16+9 =25

but there is not enough info we need another angle or side length

yes the total will be same because in both of them the expression.is rearranged but their sign remains the same hence it hss just been shuffled