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Imma juss solve question r

Using Pythagoras, 13^2 = 5^2 + |BC|^2

Therefore, 169 = 25 + |BC|^2

then, 144 = |BC|^2

so |BC| is 12cm (root of 144)

To find AC which is marked r, substituting BC as 12 and AB as 5, we can also use Pythagoras' Theorem to solve

Therefore, 12^2 = 5^2 + r^2

144 = 25 + r^2

r^2 = 144 - 25

r^2 = 119 and r = √119 = 10.9 or 11

omg what happend to your question? if you could edit this question i can

step-by-step explanation:

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