The perimeter of Rectangle A is two times that of Rectangle B. Rectangle B is 8 cm long and 9 cm wide. Given that Rectangle A and Rectangle B are similar,
what is the perimeter of Rectangle A?
A. 68 cm
B. 34 cm
C. 144 cm
D. 72 cm

A) 68 cm

Rectangles have 4 sides so you would take 8(2) and 9(2) and get 16 + 18 = 34 for rectangle B. Because rectangle A is twice the size of rectangle B, you would just take 34 and double it to get 68.

A. 68 cm

Explanation

Rectangles have 2 pairs of parallel sides, so you should multiply both sides by two.

(8•2)+(9•2)=34

Since rectangle a perimeter is two times that of rectangle b perimeter, then you should find the perimeter of rectangle b and multiply it by two.

34•2=68

So the perimeter of rectangle a is 68cm.

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