If (a-2)^2+(b+1)^2+(c-3)2 =0 then the value of a^2/4+b^2+c^2/3

5

Step-by-step explanation:

(a-2)^2+(b+1)^2+(c-3)^2 =0

Since all 3 terms are square numbers, they must be = 0 to have a sum of 0.

so a-2= 0, b+1=0 and c-3= 0

a^2/4+b^2+c^2/3= 4/4+1+9/3= 1+1+3= 5

the expression (1.26)2t reveals the approximate rate of increases in the number of plants semiannually.

hope this : )

"image"

step-by-step explanation:

in most of these problems, the notation is that the point with a "prime" is the image of the point without. that is, b' is the image of b.

here, there is no dilation or reflection. there is simply translation (with no direction shown). which figure you call the "preimage" and which one you call the "image" is up to you. as a matter of convention, the naming is as described above.