The function, f(x) = –2x2 + x + 5, is in standard form. The quadratic equation is 0 = –2x2 + x + 5, where a = –2, b = 1, and c = 5. The discriminate b2 – 4ac is 41. Now, complete step 5 to solve for the zeros of the quadratic function. 5. Solve using the quadratic formula.
x = StartFraction negative b plus or minus StartRoot b squared minus 4 a c EndRoot Over 2 a EndFraction

What are the zeros of the function
f(x) = x + 5 – 2x2?

24/56=hx^7

step-by-step explanation:

answer

false

explanation

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da freeck kinda math is this just drop out

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