I am thinking of 3 consecutive numbers less than 100.The first number has 5 as one of its factors, the second number has 1 as its factors and the last number has 2 a one of its factors

10, 11 and 12.

Step-by-step explanation:

A number has 5 as one of its factors, when last digit is 5 or 0. Only prime numbers have 1 as the only factor and a number has 2 as one of its factors when last digit is 2, 4, 6, 8 or 0.

Three possible consecutive numbers are 10, 11 and 12. 10 is the product of 2 and 5, 11 is a prime number and 12 is the product of 3 and 2². Therefore, possible choice is 10, 11 and 12.

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