Two forces, F1 and F2, are represented by vectors with initial points that are at the origin. The first force has a magnitude of 40 lb and the terminal point of the vector is point P(1, 1, 0). The second force has a magnitude of 60 lb and the terminal point of its vector is point Q(0, 1, 1). Let F be the resultant force of forces F1 and F2. (a) Find the magnitude (in pounds) of F. (Round the answer to one decimal place.)
(b) Find the direction of F.

Step-by-step explanation:

The two force F1 and F2  are represented by vectors with initial points that are at the origin.

the terminal point of the vector is point P(1, 1, 0)

Therefore, the direction of the vector force is

The unit vector in the direction of force will be

The magnitude of the force is 40lb, so the force will be

The terminal point of its vector is point Q(0, 1, 1)

Therefore, the direction of the vector force is

The magnitude of the force is 60lb, so the force will be

The resultant of the two forces is

The magnitude force will be

to (1 decimal place)=55.7lb

b) The direction angle of force F

The angle formed by F and x axis

The angle formed by F and y axis

The angle formed by F and z axis

answer: 21$

step-by-step explanation:

$42 / $14 = 3   (ratio 3: 1)

$7 x 3 = $21

the solution is h=10 because you add 9 to each side of the equation.