Four different positive integers have a product of 110.
What is the sum of the four integers?

Given:

Four different positive intergers as a product of 110

To find:

The sumnof the four numbers whose product is 110

Solution:

1) To find the number we have to find the prime factorization of the given number 110

2) Prime factorization of 110 is

110 = 1×2 × 5 = 11

3) So the four numbers whose product is 110 are 1,2,5 and 11

4) The sum of number's are

1+2+5+11=19

wheres graph

step-by-step explanation:

- 2 + 10x³ - 21x² + 19x - 4

step-by-step explanation:

each term in the second factor is multiplied by each term in the first factor

x²(- 2x² + 4x - 1) - 3x(- 2x² + 4x - 1) + 4(- 2x² + 4x - 1) ← distribute

= - 2 + 4x³ - x² + 6x³ - 12x² + 3x -8x² + 16x - 4

collect like terms

= - 2 + 10x³ - 21x² + 19x - 4 ← in standard form