The waiting times between a subway departure schedule and the arrival of a passenger are uniformly distributed between 0 and 7 minutes. Find the probability that a randomly selected passenger has a waiting time greater than 2.25 minutes.

The probability that a randomly selected passenger has a waiting time greater than 2.25 minutes is P=0.68.

Step-by-step explanation:

For a uniform distribution, any value within the minimum and maximum value have the same probability. Outside that interval, the probability is 0.

Then, for a uniform distribution within a and b, the probability P(X>c), being z<c<b is:

For our case, with a uniform distribution within 0 and 7 minutes, the probability that a randomly selected passenger has a waiting time greater than 2.25 minutes is:

i think it is x = 1.2

f(x) = x^3 -2x^2 -3x

x( x^2 -2x-3)

x( x^2 +x -3x -3)

x( x(x+1) -3(x+1))

x( x-3)( x+1)

so zeroes are 0, 3,-1

its (2) option