Hallar las dimensiones del rect´angulo de ´area m´axima que se puede inscribir en la regi´on encerrada por una par´abola de ecuaci´on y 2 = 4px y la recta x = a, donde p y a son constantes reales positivas.

step-by-step explanation:

step-by-step explanation:

there is a formula i can give you:

it is r^2*n*sin(360/n) divided by 2 where r represents the "radius" and n is the number of sides.

plug them in:

(10sqrt(3))^2*6*sin(360/6) divided by 2

100*3*6*sin(60) divided by 2

900*sin(60)

900*sqrt(3)/2

450*sqrt(3)

approx is 779.4 cm^2

my guess would be b and d, but i didn’t actually get out the pen and paper. lol

there are no choices to this, can you give us some choices so that i can answer it

step-by-step explanation: