The mapping of DEFG to D'E'F'G' is shown. 2 parallelograms have identical side lengths and angle measures. The second parallelogram is a reflection of the first. Which statements are true regarding the transformation? Check all that apply. EF corresponds to E'F'. FG corresponds to G'D'. ∠EDG Is-congruent-to ∠E'D'G' ∠DEF Is-congruent-to ∠D'E'F' The transformation is not isometric. The transformation is a rigid transformation.

(A)EF corresponds to E'F'

(C)∠EDG Is-congruent-to ∠E'D'G'

(D)∠DEF Is-congruent-to ∠D'E'F'

(F)The transformation is a rigid transformation.

Step-by-step explanation:

Given:

The following applies:

Now, a rigid transformation is a transformation of the plane that preserves length. Since the two parallelograms have identical side lengths:

Note that a reflection is an isometric transformation. Therefore the statement "The transformation is not isometric" is INCORRECT.

FG and GD are adjacent sides, therefore they may not necessarily be congruent. Thus FG does not corresponds to G'D'

in the attachment.   i didn't see your choices.   the word which means there is choices.

step-by-step explanation:

(x,y)

x tells you how much left or right you go from the origin

y tells you how much down or up you go from the origin

so for example (-3,2), you go left 3 and up twice. i denoted which of the ordered pairs is which in my graph.