Use the given probability value to determine whether the sample results could easily occur by chance, then form a conclusion. A study of the effect of seatbelt use in head-on passenger car collisions found that drivers using a seatbelt had a 64.1% survival rate, while drivers not using a seatbelt had a 41.5% survival rate. If seatbelts have no effect on survival rate, there is less than a 0.0001 chance of getting these results. What do you conclude?

As the P-value is very low, we can conclude that there is enough evidence to support the claim that the survival rate is significantly higher when the seatbelt is used.

Step-by-step explanation:

We have a hypothesis test that compares the survival rate using the seatbelt versus the survival rate not using it.

The claim is that the survival rate (proportion) is significantly higher when the seatbelt is used.

Then, the null hypothesis is that the seatbelts have no effect (both survival rates are not significantly different).

The P-value is the probabilty of the sample we have, given that the null hypothesis is true. In this case, this value is 0.0001.

This is very low, what gives enough evidence to claim that the survival rate is significantly higher when the seatbelt is used.

x =±sqrt(1/3)

step-by-step explanation:

x+4/6x=1/x

multiply each side by 6x to get rid of the fractions

6x*(x+4/6x)=1/x*6x

distribute

6x^2 +4 = 6

subtract 4 from each side

6x^2 +4-4 = 6-4

6x^2 =2

divide by 6

6x^2/6 = 2/6

x^2 = 1/3

take the square root of each side

sqrt(x^2) = ±sqrt(1/3)

x =±sqrt(1/3)

the surface area is 124cm²

step-by-step explanation:

length: 4cm

width: 9cm

height:   2cm