A preliminary sample of holiday shoppers revealed that the standard deviation of the amount of money they are planning to spend on gifts during the coming holiday season is $80. How many holiday shoppers should be sampled in order to estimate the average amount of money spent on gifts by all holiday shoppers with a margin of error of $7 and with a 99% confidence

So the answer for this case would be n=870 rounded up to the nearest integer

Step-by-step explanation:

Information given

represent the deviation

ME = 7 represent the margin of error

Solution

The margin of error is given by this formula:

   (a)

And on this case we have that ME =7 and we are interested in order to find the value of n, if we solve n from equation (a) we got:

  (b)

The critical value for 99% of confidence interval now can be founded using the normal distribution. The significance level would be and . The critical value would be , replacing into formula (b) we got:

So the answer for this case would be n=870 rounded up to the nearest integer

in english this is

ex.15 pag.85 create. write in ten lines the continuation of the ballad of the five motanasi, using verbs to the imperfect and to the perfect compound. five stars

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