Given: m∠AOB=50°, m∠FOE=70°. Find: m∠AOC, m∠BOD, m∠COE and m∠COD.

m∠AOC= 120°

, m∠BOD = 130°

m∠COE = 110°

m∠COD.= 60°

Step-by-step explanation:

Let's note that

AOF = COD= 60°

BOC = FOE= 70°

AOB = DOE= 50°

Given: m∠AOB=50°, m∠FOE=70°. m∠AOC

, m∠BOD,

m∠COE

m∠COD. = AOF = (360-(2(70)+2(50)))/2

AOF = (360-240)/2

AOF = 120/2

AOF = 60°= COD

COE = COD+DOE= 60+50= 110°

BOD = BOC + COD = 70+60= 130°

AOC = AOB + BOC = 50+70 = 120°

solution:

→c= a b , that is product of a and b is possible only when when a is m × n matrix and b is n × p matrix.

that is, number of columns of a= number of rows of b.

so, size of matrix , c= a b is , if a = (m × n)matrix

b= (n × p)matrix

then a b = [ (m × n)matrix] ×[   (n × p)matrix ]

→→c= a b= [m × p ] matrix

→→size of product a b will be equal to = number of rows of a × number of columns of b