What is the area of the shaded portion of the circle? (16π – 32) in2 (16π – 8) in2 (64π – 32) in2 (64π – 8) in2

(16π - 32) in²

Step-by-step explanation:

In the picture attached, the circle is shown.

Area of one-quarter of circle = 1/4*Area of a circle = 1/4*π*radius² = 1/4*π*8² = 16π in²

Area of the triangle = 1/2*base*height = 1/2*8*8 = 32 in²

Shaded area = Area of one-quarter of circle - Area of the triangle = (16π - 32) in²

#1 (16π - 32) in²

Step-by-step explanation:

Hope this helps!

Brainliest if correct pls

tangent

step-by-step explanation: