Given that sec x - tan x=1÷4

Let =tan2

t

=

tan

⁡

x

2

, then cos=1−21+2

cos

⁡

x

=

1

−

t

2

1

+

t

2

and tan=21−2

tan

⁡

x

=

2

t

1

−

t

2

.

Now

1+21−2+21−2(1+)21−21+1−tan2

Step-by-step explanation:

find the vertical and horizontal asymptotes of the function f x = 5 x − 1 . to find the vertical asymptote, equate the denominator to zero and solve for . since the degree of the polynomial in the numerator is less than that of the denominator, the horizontal asymptote is .

step-by-step explanation:

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step-by-step explanation:

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