Find the 24th term of an arithmetic sequence for which a_1 = 2 and d = 6.

140

Step-by-step explanation:

The n th term of an arithmetic sequence is

= a₁ + (n - 1)d

where a₁ is the first term and d the common difference

Here a₁ = 2 and d = 6 , thus

= 2 + (23 × 6) = 2 + 138 = 140

 a₂₄ = 140

Step-by-step explanation:

The formula for an arithmetic sequence is:  where

Given: a₁ = 2, d = 6, n = 24

a₂₄ = 2 + 6(24 - 1)

     = 2 + 6(23)

     = 2  + 138

    = 140

The 24th term is 140.

2x^2+5x+17

your welcome. : )

false

step-by-step explanation:

the reason i say this is because for a certain length of sides you can pick any two and the length is wither equal or greater than the third side and in this case it's not.

3 + 5 = 8

8 is smaller than 9 which is the third side.

hope this : )