Rearrange the following steps in the correct order to locate the last occurrence of the smallest element in a finite list of integers, where the integers in the list are not necessarily distinct. a. return location
b. min ≔a1 and location ≔1
c. min ≔ai and location≔i
d. procedure last smallest(a1,a2,...,an: integers)
e. If min >= ai then

The rearranged steps is as follows:

d. procedure last smallest(a1,a2,...,an: integers)

b. min ≔a1 and location ≔1

e. If min >= ai then

c. min ≔ai and location≔i

a. return location

Step-by-step explanation:

The proper steps to perform the task in the question above is dbeca

Here, the procedure (or function) was defined along with necessary parameters

d. procedure last smallest(a1,a2,...,an: integers)

The smallest number is initialized to the first number on the list and its location is initialized to 1

b. min ≔a1 and location ≔1

The next line is an if conditional statement that checks if the current smallest number is greater than a particular number

e. If min >= ai then

If the above condition is true, the smallest value is assigned to variable min; it's location is also assigned to variable location

c. min ≔ai and location≔i

The last step returns the location of the smallest number

a. return location

step-by-step explanation:

3+x

step-by-step explanation: