The sum of three numbers is 75. The first number is 5 more than the second. The third number is 2 times the first. What are the numbers?

The numbers are: 16, 11 and 48

Step-by-step explanation:

Let 1st number is a, second number is b and third number is c

1st number is 5 more than the second so a=b+5

The third number is 2 times the first so c=3*a=3*(b+5)

The sum of three numbers, so a+b+c=b+5+b+3*(b+5)=75

b+5+b+3+3b+15=75

5b+20=75

5b=55

b=11

a=b+5=11+5=16

c=3*(b+5)=3*(11+5)=3*16=48

The numbers are: 16, 11 and 48

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step-by-step explanation: