How many solutions does x^2 - 5x + 40 = 0 have? Choices: 0, 1 (double root), or 2?

0 real roots or 2 complex roots

Step-by-step explanation:

Discriminant: b² - 4ac

If d > 0, then there are 2 real zeros

If d = 0, then there is 1 real zero

If d < 0, then there are 0 real zeros and 2 complex/imaginary zeros

Simply substitute a = 1, b = -5, and c = 40

Our d should equal -135, showing us we have 0 real roots and 2 complex ones.

i only know the sequence of arithmetic it adds the first is 5+4 then it goes up as it adds to then it is 9+5 then 14+6 then to 20+7 and so on. 5,9,14,20,27,35.

step-by-step explanation: