Please I have been asked to factor:
x^2 -8x -16

It's unfactorable

Step-by-step explanation:

x² - 8x - 16 is already in its simplest form. You cannot take GCF or x out. Also, nothing multiplies to -16 and adds up to -8.

unfactorable

Step-by-step explanation: To factor x² - 8x - 16, we set up our two binomials with x and x as the first position in each binomial.

To fill the second position, we want to

look for factors of -16 that add to -8.

Factors of -16

+16 · -1

-16 · +1

+8 · -2

-8 · + 2

+4 · -4

So what pair of factors add to -16.

Well, none of them do.

When that happens, we say that the original

trinomial is unfactorable and that's your answer.

a) y = -3x +2

b) y = 1/2x -6

these 2 can be combined into one equation.

-3x +2 = .5x -6

8 = 3.5x

x = 8 / 3.5 = 2.2857142857

y = -3 * (8 / 3.5) +2

y = (-24 / 3.5) + 2

y = -4.8571428571

step-by-step explanation:

the answer would be d.

step-by-step explanation:

move all variables to the left side and all constants to the right side

(x−3)^2+(y−1)^2=16

this is the form of a circle. use this form to determine the center and radius of the circle.

( x − h ) 2 + ( y − k ) 2 = r 2

match the values in this circle to those of the standard form. the variable   r   represents the radius of the circle,   h   represents the x-offset from the origin, and   k   represents the y-offset from origin.

r = 4

h = 3

k = 1

the center of the circle is found at   ( h , k ) .

center:   ( 3 , 1 )

these values represent the important values for graphing and analyzing a circle.

center:   ( 3 , 1 ).

radius:   4