Find the probability that when a couple has twotwo children, at least one of them is a boyboy. (Assume that boys and girls are equally likely.) The probability is . 5.5 that at least one of the twotwo children is a boyboy.

0.75

Step-by-step explanation:

It is given that having a boy or girl as children are the two events which are equally likely.

i.e. Probability of having a boy or a girl is equal to or 0.5.

Let P(B) be the probability of having a boy and P(G) be the probability of having a girl child.

So, P(B) = P(G) = 0.5

To find: Probability that out of two children, atleast one boy is born.

Required probability  = 1 - Probability that both the children are girls

Required probability :

So, the probabilty that atleast one boy is born out of two children is 0.75.

c.

step-by-step explanation:

substitution for (0,1)

y=x^2+4x+1

1=0^2+4(x)0+1

1=0+4(x)0+1

1=4(x)0+1

1=0+1

1=1

substitution for (-3,-2)

y=x+1

-2=-3+1

-2=-2

to complete this square you have to rotate about the origin 270 degrees clockwise.