guys gelp me plzzz £ represents a group of 30 people that visited paris for a weekend break. 13 of the group visited the eiffel tower (ET) 16 of the group visited the no tre-dame cathedral (NDC) 7 of the group did not visit either of these places a person is chosen at random from the group. what is the probability that this person only visited one of the two places?

57%

Step-by-step explanation:

Data provided in the questions

Total people visited paris for weekend break = 30

Out of which

Group of 13 visited the eiffel tower (ET)

The other group of 16 visited the no tre-dame cathedral (NDC)

And, the remaining 7 did not visited any place

Now to find out the person visited only one of the two places we need to divide it by the total number of persons visited at one place only by the total number of persons

So, the total number of persons visited at one place only is

= 13 + 16

= 29

And if we add 7 persons so it would be 36

But in actual it is 30 people so there is an addition of 6 persons

That means these 6 persons visited two places so we ignored it in both the groups

So.

For eiffel tower

= 13 - 6

= 7

And for Cathedral, it would be

= 16 - 6

= 10

Now add these two

= 10 + 7

= 17

So, the probability would be

= 57%

6mm^3 or .6cm^3

      216

      /   \

  36     6

  /   \     /

6     6   6

factor trees are nice.