You and your friend are rolling number cubes. Each cube has 6 sides with the numbers 1 to 6. If a sum of 7 is rolled, your friend gets a point. However, you get a point if either one of the sums listed below is rolled. Which pair of numbers would make the game fair? 12 and 8 12 and 10 2 and 5 2 and 12

12 and 8

Step-by-step explanation:

The following 6 outcomes add 7: {1, 6}, {2,5}, {3,4}, {4,3}, {5,2} and {6,1}

The following 1 outcome adds 12: {6, 6}

The following 5 outcomes add 8: {2,6}, {3,5}, {4,4}, {5,3} and {6,2}

Therefore the pair 12 and 8 would make the game fair, because both players have 6 favourable outcomes

i need a picure

step-by-step explanation:

step-by-step explanation:

a cube has 6 sides

the probability of getting 5 on the first cube is 1/6 since only one side of the cube has 5 on it.

there are 3 sides of the cube with even number on it [2,4,6]

therefore the probability of getting even number is 3/6

for both events to happen together, the probability would be

1/6 x 3/6 = 12/36

which simplifies to 1/12