The heights of 10 year old children has a normal probability distribution with mean of 54.6 inches and standard deviation of 5.7 inches. What is the approximate probability that a randomly selected 10-year old child will be more than 51.75 inches tall? Group of answer choices 0.69 0.31 0.62 0.67 0.93

a) 0.69

The probability that a randomly selected 10-year old child will be more than 51.75 inches tall

P(X>51.75 ) = 0.6915

Step-by-step explanation:

Step(i):-

Given mean of the Population = 54.6 inches

Given standard deviation of the Population = 5.7 inches

Let 'X' be the random variable of normal distribution

Let 'X' = 51.75 inches

Step(ii):-

The probability that a randomly selected 10-year old child will be more than 51.75 inches tall

P(X>51.75 ) = P(Z>-0.5)

                  = 1 - P( Z < -0.5)

                 =   1 - (0.5 - A(-0.5))

                =    1 -0.5 + A(-0.5)

               =    0.5 + A(0.5)    (∵A(-0.5)= A(0.5)

              =     0.5 +0.1915

              =  0.6915

Conclusion:-

The probability that a randomly selected 10-year old child will be more than 51.75 inches tall

P(X>51.75 ) = 0.6915

all the angles opposite to the angle 150 would be 150 and all the angles that are next to 150 are 30 because they equal 180 it you add it up.

step-by-step explanation:

1/8 3/16 3/4

step-by-step explanation:

you put them as all the same denominator and multiply