Use a graphing utility to determine the first term that is less than 0.0001 in each of the convergent series. Note that the answers are very different. (If necessary round your answers up to the next integer value. Explain how this will affect the rate at which the series converges. a. ∑_(n=1)^[infinity] 1/2^n b. ∑_(n=1)^[infinity] (0.01)^n

the answer is d. 75%

-6 is the correct option from the above given options

if gloria has "carry over" minutes, (that is, any minutes paid for but not used in a month can be applied to her payment for minutes in the next month,) her total usage for the three months is: total minutes = 320 + 243 + 489 = 1052 minutes number of 200 minute blocks = 1052/200 = 5 r52 (that is 5 with a remainder of 52) rounding up the number of 200 minute blocks gives her usage for the three months as 6 blocks. the cost for six blocks is 6 x $25 = $150 she also has 200 - 52 or 148 carry over minutes if gloria pays each month and unused minutes are lost, applying the rounding up procedure to each month gives: first month usage of 320 minutes rounds up to 2 blocks of 200 minutes for a payment of 2 x $25 = $50 second month usage of 243 minutes rounds up to 2 blocks of 200 minutes for a payment of 2 x $25 = $50 third month usage of 489 minutes rounds up to 3 blocks of 200 minutes for a payment of 3 x $25 = $75 total payments for the three months are $50 + $50 + $75 = $175 get the plan with carry over minutes!

just pick what you think i need more time let me know if this

step-by-step explanation: