Help asap please will give brainliest

d. (x+2)/(-x²-5)

Step-by-step explanation

 ƒ(x) = x + 2/(2x²)

The function is undefined when x =  0.

b. ƒ(x) = (2x + 4)/(3x + 3)

The function is undefined when 3x + 3 = 0, i.e., when x = -1.

c. ƒ(x) = (6x - 5)/(x² - 7)

The function is undefined when x² - 7 = 0, i.e., when x = √7.

d. ƒ(x) = (x+2)/(-x²-5) = -(x+2)/(x² + 5)

The function would be undefined if x² + 5 = 0, i.e., if x² = -5. However, the square of a real number cannot be negative.

This function has no excluded values.

(1, –1), (16, –4), (36, –6)

step-by-step explanation:

given that the function is

this can also be written as

we have to graph this function and check which list of points lie on the graph

see attachment for graph:

we find that the points lying are (1,-1) (16,-4) and (36,-6)

since square root is there we find that x can only be posiitve but y can be since square root both positive and negative.

step-by-step explanation: